So one can write
∑ i γ i c V , i C ~ V = α K T C V ρ = α V K T C ~ V {\displaystyle {\frac {\sum _{i}\gamma _{i}c_{V,i}}{{\tilde {C}}_{V}}}={\frac {\alpha K_{T}}{C_{V}\rho }}={\frac {\alpha VK_{T}}{{\tilde {C}}_{V}}}}
This way, it suffices to prove
∑ i γ i c V , i = α V K T {\displaystyle \sum _{i}\gamma _{i}c_{V,i}=\alpha VK_{T}}
Left-hand side (def):
