User:Nukeh/Sandbox
KE = PE = ¼ ρ g a², so E = ½ ρ g a²
\text{PseudoInverse}[\text{dict}]=\alpha
^{1-\text{word}}
\text{dict}^{\unicode{F3C7}}-\frac{\alpha
^{-\text{word}} (\text{word}-1)}{\text{word}}
KE = PE = ¼ ρ g a², so E = ½ ρ g a²
\text{PseudoInverse}[\text{dict}]=\alpha
^{1-\text{word}}
\text{dict}^{\unicode{F3C7}}-\frac{\alpha
^{-\text{word}} (\text{word}-1)}{\text{word}}