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12 July 2025
- diffhist m Tangent space 11:45 +1 BrianGroenke talk contribs (Add missing comma)
10 July 2025
- diffhist Template:Tmath 23:28 +8 Jacobolus talk contribs (Undid revision 1299875796 by Jacobolus (talk) this still doesn't seem to be working properly. not quite sure what the issue is) Tag: Undo
- diffhist Template:Tmath 23:17 −8 Jacobolus talk contribs (Undid revision 1234073114 by Quondum (talk) unfortunately this version doesn't work) Tags: Undo Reverted
9 July 2025
- diffhist Sobolev space 01:35 +1 2601:204:f181:9410:6153:6620:da52:efb3 talk (→One-dimensional case: Added comma)
- diffhist Sobolev space 01:18 0 2601:204:f181:9410:6153:6620:da52:efb3 talk (→Motivation)
- diffhist Sobolev space 01:17 +32 2601:204:f181:9410:6153:6620:da52:efb3 talk (→Motivation: Improved phrasing)
8 July 2025
- diffhist Continuous function 15:49 +19 2601:204:f181:9410:6d18:79a7:3041:62d2 talk (→Semicontinuity)
- diffhist Continuous function 15:46 +42 2601:204:f181:9410:6d18:79a7:3041:62d2 talk (→Directional Continuity: Improved wording)
7 July 2025
- diffhist Set (mathematics) 21:00 +3 D.Lazard talk contribs (→Algebra of subsets: "The set" refers to U, not to any subset)
- diffhist Set (mathematics) 10:17 +8 Jochen Burghardt talk contribs (Undid revision 1299255997 by D.Lazard (talk): agree with Ifoundamistake75475: A \Delta A = (A \ A) \cup (A \ A) = {} \cup {} = {}, i.e. the additive inverse, while A \Delta A' = (A \ A') \cup (A' \ A) = A \cup A' = U, when A' denotes the absolute complement) Tag: Undo
- diffhist Set (mathematics) 09:28 −8 D.Lazard talk contribs (Reverted 1 edit by Ifoundamistake75475 (talk): Was corect) Tags: Twinkle Undo Reverted
- diffhist Set (mathematics) 06:39 +8 Ifoundamistake75475 talk contribs (→Algebra of subsets: I believe I found a mistake. In the boolean ring that is the powerset of a given set, when you are using the additive operation (symmetric difference), the additive inverse (a number x such that a+x=0 for all a) is not its complement, as by applying symmetric difference (any elements contained in two sets but not both), you can see that the complement (all elements not a part of A is the complement of A) when added to a set results in simply the union (all elements a p...) Tags: Reverted Mobile edit Mobile web edit