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{\displaystyle u_{ind}=\oint {\vec {E}}d{\vec {s}}=-N{{d\Phi } \over {dt}}}
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{\displaystyle \oint {\vec {E}}d{\vec {s}}1=-u_{1}=-N{{d\Phi 1} \over {dt}}}
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{\displaystyle {{-u_{1}(t)} \over {N_{1}}}={{\oint _{s1}{\vec {E}}d{\vec {s}}_{1}} \over {N_{1}}}={{-d\Phi } \over {dt}}={{\oint _{s2}{\vec {E}}d{\vec {s}}_{2}} \over {N_{2}}}={{-u_{2}(t)} \over {N_{2}}}}
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{\displaystyle N_{2}\cdot u_{1}(t)=N_{1}\cdot u_{2}(t)}
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{\displaystyle \Phi _{2}-\Phi _{1}=\int _{t_{1}}^{t_{2}}u_{1}(t)dt}
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{\displaystyle \mu _{r}\to \infty }
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{\displaystyle \oint Hds=N_{1}\cdot i_{1}(t)+N_{2}\cdot i_{2}(t)=0}
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{\displaystyle N_{1}\cdot i_{1}=-N_{2}\cdot i_{2}}
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{\displaystyle u_{ind}=\oint {\vec {E}}d{\vec {s}}}
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{\displaystyle \oint {\vec {E}}d{\vec {s}}}
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{\displaystyle \oint {\vec {E}}d{\vec {s}}=0}
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{\displaystyle \Phi (t_{2})-\Phi (t_{1})={{-1} \over N_{1}}\cdot \int _{t1}^{t2}u_{1}(t)dt<\infty }
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I
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{\displaystyle \oint Hds=\sum I=0}
