--Kito 00:07, 3. Mai 2006 (CEST)
Hehe xD
P ( X ≤ k ) = ∑ i = 0 k ( 10 i ) ⋅ 0 , 2 i ⋅ 0 , 8 10 − i ≥ 0 , 95 {\displaystyle P(X\leq k)=\sum _{i=0}^{k}{\binom {10}{i}}\cdot 0{,}2^{i}\cdot 0{,}8^{10-i}\geq 0{,}95}
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