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Hausaufgabe Diskrete Strukturen
von Maximilian Deutsch
Ausgabe am: 21.10.05
A = { a, 23, 4}
B = { a,
δ
{\displaystyle \delta }
2, 3, 42}
C = {
α
{\displaystyle \alpha }
,
∈
{\displaystyle \in }
, 2, 3}
D = B
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
C )
E = D
∩
{\displaystyle \cap }
( A
∩
{\displaystyle \cap }
B )
F = E
∪
{\displaystyle \cup }
( A \ C )
G = F
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
B )
D in E in F in G
G = ((( B
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
C ))
∩
{\displaystyle \cap }
( A
∩
{\displaystyle \cap }
B ) )
∪
{\displaystyle \cup }
( A \ C ) )
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
B )
( A
∪
{\displaystyle \cup }
C ) = { a,
α
{\displaystyle \alpha }
,
∈
{\displaystyle \in }
, 2, 3, 23, 42 }
( A
∩
{\displaystyle \cap }
C ) = { a, 42 }
( A \ C ) = { 23, 42 }
( A
∪
{\displaystyle \cup }
B ) = { a,
δ
{\displaystyle \delta }
, 2, 3, 23, 42 }
D = B
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
C ) = { a, 2, 3, 42 }
E = D
∩
{\displaystyle \cap }
( A
∩
{\displaystyle \cap }
B ) = { a, 42 }
F = E
∪
{\displaystyle \cup }
( A \ C ) = { a, 23, 42 }
G = F
∩
{\displaystyle \cap }
( A
∪
{\displaystyle \cup }
B ) = { a, 23, 42 }
|P (G)| = 2³ = 8