N α N β = e − Δ E k T = e − ( E 1 − E 2 ) k T {\displaystyle {\frac {N_{\mathrm {\alpha } }}{N_{\mathrm {\beta } }}}=\mathrm {e} ^{-\Delta E \over kT}=\mathrm {e} ^{-(E_{1}-E_{2}) \over kT}}
k = R N L = 8,314 J ⋅ m o l 6,023 ⋅ 10 23 m o l ⋅ K = 1 , 38 ⋅ 10 − 23 J K {\displaystyle k={\frac {R}{N_{L}}}={\frac {8{,}314J\cdot mol}{6{,}023\cdot 10^{23}mol\cdot K}}=1{,}38\cdot 10^{-23}{\frac {J}{K}}}
N α N β {\displaystyle {\frac {N_{\mathrm {\alpha } }}{N_{\mathrm {\beta } }}}}
δ = v P r o b e − v T M S v T M S ⋅ 10 6 p p m {\displaystyle {\delta }={\frac {v_{Probe}-v_{TMS}}{v_{TMS}}}\cdot 10^{6}ppm}
v = γ B 0 2 π {\displaystyle v={\frac {{\gamma }B_{0}}{2{\pi }}}}
Δ E = h ⋅ v {\displaystyle {\Delta }E=h\cdot v}
g m o l {\displaystyle {\frac {g}{mol}}}
g c m 3 {\displaystyle {\frac {g}{cm^{3}}}}
p g e s < p a + p b {\displaystyle p_{ges}<p_{a}+p_{b}}
