Talk:Differentiating Functions

The printable version is no longer supported and may have rendering errors. Please update your browser bookmarks and please use the default browser print function instead.

This article was nominated for deletion on 28 October 2005. The result of the discussion was no consensus.

Untitled

Admiral Payne 18:44, 25 October 2005 (UTC)[reply]

Okay, I edited the main article's part from f(x+dx)-f(x) -> (x+dx)^n-x^n..

Maybe this needs a little more explaining.

We had f(x+dx)-f(x) for starters. Now we filled this into f(x)=x^n, because this is the main function we want to prove. That would mean; we put (x+dx) and (x) as 'x' into f(x).. Thus leading to:

(x+dx)^n-x^n