Talk:Solving quadratic equations with continued fractions
Comments
Why are we only using examples of period 1? Septentrionalis PMAnderson 03:54, 13 December 2006 (UTC)
- We want to explain the simplest case of a periodic continued fraction first, so the article will be accessible to people with little mathematical sophistication. Any infinite periodic continued fraction can be transformed into a periodic cf of period 1, by a relatively straightforward algebraic substitution. But shouldn't something like that go in its own article, maybe "Periodic continued fraction"? DavidCBryant 11:27, 14 December 2006 (UTC)
Your general theorem cannot be true as stated; x2 - 2 has a perfectly good continued fraction for the positive root (and for that matter, the negative root) despite having b = 0; I think I see what is meant, but it's not what is said. Septentrionalis PMAnderson 04:08, 13 December 2006 (UTC)
- Well, I thought it was clear from the context that the theorem refers to the general formula for the solution to a quadratic equation. But on reflection, I do see what you mean. More verbiage has been added. Does it look better now?
- Oh -- there was another error in the statement of the theorem. The trick with the discriminant only works when the equation has real coefficients. It's a bit more complicated when the coefficients are complex numbers, because the value of the discriminant doesn't have to be a real number in that case. For now the section has been adjusted to speak only of equations with real coefficients. The statement about complex coefficients will be added soon, along with a proof (in a separate article) of the theorem. Would you be kind enough to kick the tires on that stuff, too?
- Thanks for the help with this article, Septentrionalis! DavidCBryant 11:27, 14 December 2006 (UTC)
The section about complex coefficients has been added. There's a red link to convergence problem, which should get fixed in the next couple of days. DavidCBryant 20:26, 14 December 2006 (UTC)