Elementary comparison testing

Elementary comparison testing (ECT) is a formal white-box, control-flow, test-design method. Its purpose is to implement the detailed testing of complex and important software. Software pseudocode or code is tested to assess the proper handling of all decision outcomes. As with multiple-condition coverage and basis path testing, coverage of all independent isolated condition paths is accomplished through modified condition/decision coverage (MC/DC). Isolated conditions are aggregated into connected situations creating test cases. The independence of a condition is shown by changing the condition value in isolation. Each relevant condition value is covered by test cases.

A test case

A test case consists of a logical consonant path from start to end passing one or many decisions. Contradicting situations are excluded and deduced from the test case matrix. The MC/DC approach isolates every condition neglecting all possible subpath combinations and path coverage

$T=n+1$

where

• T is the amount of test cases per decision, and
• n the amount of conditions.

The decision $d_{i}$ consists of a combination of elementary conditions

${\begin{aligned}\Sigma &=\{0,1\}\\C&=\{c_{0},c_{1},c_{2},c_{3},...,c_{n}\}\end{aligned}}$

$\epsilon :C\rightarrow \Sigma \times C$

$D\subseteq C^{*};d_{i}\in D.$

The transition function $\alpha$ is defined as

$\alpha :D\times \Sigma ^{*}\rightarrow \Sigma \times D.$

Given the transition $\vdash$

$\vdash \subseteq (\Sigma \times D\times \Sigma ^{*})\times (\Sigma \times D\times \Sigma ^{*})$

$S_{j}=(b_{j},d_{m},v_{j})\vdash (b_{j+1},d_{n},v_{j+1})$
$E_{j}=(a_{j},c_{j})\vdash (a_{j+1},c_{k})$
$(b_{j+1},d_{n})=\alpha (d_{m},v_{j});(b_{j+1},c_{k})=\epsilon (c_{j});a_{j}\in \Sigma ,$

the isolated test path $P_{m}$ consists of

${\begin{aligned}P_{m}&=(b_{0},d_{0},v_{0})\vdash ...\vdash (b_{i},d_{i},v_{i})\vdash ^{*}(b_{n},d_{n},v_{n})\\&=(b_{0},c_{0})\vdash ...\vdash (b_{m},c_{m})\vdash ^{*}(b_{n},c_{n})\end{aligned}}$

$b_{i}\in \Sigma ;c_{m}\in d_{i};v\in C^{*};d_{0}=S;d_{n}=E.$

Test case graph

A test case graph illustrates all the necessary independent paths (test cases) to cover all isolated conditions. Conditions are represented by nodes and condition values (situations) by edges. All program situations are addressed by an edge. Each situation is connected to one preceding and successive condition. Test cases might overlap due to isolated conditions.

Inductive proof of number of condition paths

The elementary comparison testing method can be used to determine the number of condition paths by inductive proof.

Figure 2: ECT Inductive Proof Anchor

There are $r=2^{n}$ possible condition value combinations

$\forall {i}\in \{1,...,n\}\ c_{i}\mapsto \{0,\ 1\}$.

When each condition $c_{i}$ is isolated, the number of required test cases $T$ per decision is:

$T=\log _{2}(r)+1=n+1.$

Figure 3: ECT Inductive Proof End

$\forall {i}\in \{1,...,n\}$ there are $0<e<i+1$ edges from parent nodes $c_{i}$ and $s=2$ edges to child nodes from $c_{i}$.

Each individual condition $c_{i}$ connects to at least one path

$\forall {i}\in \{1,...,n-1\}\ c_{i}\mapsto \{0,\ 1\}$

from the maximal possible $n$ connecting to $c_{n}$ isolating $c_{n}$.

All predecessor conditions $c_{i};\ i<n$ and respective paths are isolated. Therefore when one node (condition) is added, the total number of paths, and required test cases, from start to finish increases by:

${\begin{aligned}T&=n-1+2\\&=n+1.\end{aligned}}$

$\ q.\ e.\ d.$

Test-case design steps

1. Identify decisions
2. Determine test situations per decision point (Modified Condition / Decision Coverage)
3. Create logical test-case matrix
4. Create physical test-case matrix

Example

This example shows ETC applied to a holiday booking system. The discount system offers reduced-price vacations. The offered discounts are $-10\%$ for average customers, $-20\%$ for expensive vacations, and $0\%$ otherwise. The example shows the creation of logical and physical test cases for all isolated conditions.

Figure 4: ECT Example Control Flow Graph

Pseudocode

if days > 15 or price > 1000 or member
  return -0.2
else if (days > 8 and days < 15 or price>500 and price < 1000) and workday
  return -0.1
else
  return 0.0


Factors

• Number of days: $<8;\ 8-15;\ >15$
• Price (euros): $<500;\ 500-1000;\ >1000$
• Membership card: $none;\ silver;\ gold;\ platinum$
• Departure date: $workday;\ weekend;\ holiday$

$T=3\times 3\times 4\times 3=108$ possible combinations (test cases).

Step 1: Decisions

Figure 5: ECT Example D2 Conditions

${\begin{aligned}d_{1}&=days>15\ or\ price>1000\ Eur\ or\ member\\c_{1}&=days>15\\c_{2}&=price>1000\\c_{3}&=member\\\end{aligned}}$

${\begin{aligned}d_{2}&=(8<days<15\ or\ 500<price<1000\ Eur)\ and\ workday\\c_{4}&=8<days<15\\c_{5}&=500<price<1000\ Eur\\c_{6}&=workday\\\end{aligned}}$

Step 2: MC/DC Matrix

Table 1: Example D1 MC/DC

		Outcome
Decision D1		1			0
Conditions		c1	c2	c3	c1	c2	c3
c1	$days>15$	1	0	0	0	0	0
c2	$price>1000$	0	1	0	0	0	0
c3	$member$	0	0	1	0	0	0

Table 2: Example D2 MC/DC

		Outcome
Decision D2		1			0
Conditions		c4	c5	c6	c4	c5	c6
c4	$8<days<15$	1	0	1	0	0	1
c5	$500<price<1000$	0	1	1	0	0	1
c6	$workday$	1	0	1	1	0	0

The highlighted diagonals in the MC/DC Matrix are describing the isolated conditions:

$(c_{i},c_{i})\mapsto \{1,0\}$

all duplicate situations are striked like proven.

Step 3: Logical test-Case matrix

Table 3: Example Logical Test Case Matrix

Situation $S_{j}$	$T_{1}$	$T_{2}$	$T_{3}$	$T_{4}$	$T_{5}$	$T_{6}$	$T_{7}$
$\alpha (d_{1},\mathbf {1} 00)\mapsto (1,E)$	x
$\alpha (d_{1},\mathbf {0} 00)\mapsto (0,d_{2})$		x			x	x	x
$\alpha (d_{1},0\mathbf {1} 0)\mapsto (1,E)$			x
$\alpha (d_{1},00\mathbf {1} )\mapsto (1,E)$				x
$\alpha (d_{2},\mathbf {1} 01)\mapsto (1,E)$		x
$\alpha (d_{2},\mathbf {0} 01)\mapsto (1,E)$						x
$\alpha (d_{2},0\mathbf {1} 1)\mapsto (1,E)$					x
$\alpha (d_{2},11\mathbf {0} )\mapsto (0,E)$							x

Test cases are formed by tracing decision paths. For every decision $d_{i};\ 0<i<n+1$ a succeeding and preceding subpath is searched until every connected path has a start $S$ and an end $E$:

${\begin{aligned}T_{1}&=(d_{1},100)\vdash (1,E)\\T_{2}&=(d_{1},000)\vdash (0,d_{2},100)\vdash (1,E)\\T_{3}&=(d_{1},010)\vdash (1,E)\\\end{aligned}}$
$...$
$T_{n+1}$

Step 4: Physical test-case matrix

Table 4: Example Physical Test Cases

Factor\Test Case	$T_{1}$	$T_{2}$	$T_{3}$	$T_{4}$	$T_{5}$	$T_{6}$	$T_{7}$
days	16	14			8	8	8
price			1100			600
departure							sa
member				silver
Result
0							0
-10		1			1	1
-20	1		1	1

Physical test cases are created from logical test cases by filling in actual value representations and their respective results.

Test-case graph

Figure 6: ECT Example Test Case Graph

In the example test case graph, all test cases and their isolated conditions are marked by colors and the remaining paths are implicitly passed.

See also

• Multiple condition coverage
• Control flow graph
• Decision to decision path