Shilov boundary

In functional analysis, a branch of mathematics, the Shilov boundary is the smallest closed subset of the structure space of a commutative Banach algebra where an analog of the maximum modulus principle holds. It is named after its discoverer, Georgii Evgen'evich Shilov.

Precise definition and existence

Let ${\mathcal {A}}$ be a commutative Banach algebra and let $\Delta {\mathcal {A}}$ be its structure space equipped with the relative weak*-topology of the dual ${\mathcal {A}}^{*}$ . A closed (in this topology) subset $F$ of $\Delta {\mathcal {A}}$ is called a boundary of ${\mathcal {A}}$ if $\max _{f\in \Delta {\mathcal {A}}}|x(f)|=\max _{f\in F}|x(f)|$ for all $x\in {\mathcal {A}}$ . The set $S=\bigcap \{F:F{\text{ is a boundary of }}{\mathcal {A}}\}$ is called the Shilov boundary. It has been proved by Shilov^[1] that $S$ is a boundary of ${\mathcal {A}}$ .

Thus one may also say that Shilov boundary is the unique set $S\subset \Delta {\mathcal {A}}$ which satisfies

$S$ is a boundary of ${\mathcal {A}}$ , and
whenever $F$ is a boundary of ${\mathcal {A}}$ , then $S\subset F$ .

Examples

Let $\mathbb {D} =\{z\in \mathbb {C} :|z|<1\}$ be the open unit disc in the complex plane and let

Failed to parse (syntax error): {\displaystyle {\mathcal A}={H^{2}(\mathbb D)\cap {\mathcal C}(\bar{\mathbb D})} be the disc algebra, i.e. the functions holomorphic in $\mathbb {D}$ and continuous in the closure of $\mathbb {D}$ with supremum norm and usual algebraic operations. Then $\Delta {\mathcal {A}}={\bar {\mathbb {D} }}$ and $S=\{|z|=1\}$ .