In geometry a circular section is a circle on a quadric surface (ellipsoid, hyperboloid, ...). It is a special plane section of the quadric, as this circle is the intersection with the quadric of the plane containing the circle.
Any plane section of a sphere is a circular section, if it contains at least 2 points. Any quadric of revolution contains circles as sections with planes that are orthogonal to its axis; it does not contain any other circles, if it is not a sphere. More hidden are circles on other quadrics, such as tri-axial ellipsoids, elliptic cylinders,... Nevertheless, it is true that:
Any quadric surface, which contains ellipses, contains circles, too.
Equivalently, all quadric surfaces contain circles except parabolic and hyperbolic cylinders and hyperbolic paraboloids.
If a quadric contains a circle, then every intersection of the quadric, with a plane parallel to this circle, is also a circle, provided it contains at least two points. The circles contained in a quadric, if any, are all parallel to one of two fixed planes (which are equal in the case of a quadric of revolution).
In order to find the planes, which contain circular sections of a given quadric, one uses the following statements:
(S:) If the common points of a quadric with a sphere are contained in a pair of planes, then the intersection curve consists of two circles.
(P:) If the intersection of a plane and a quadric is a circle, than any parallel plane, that contains at least two points of the quadric, intersects the quadic in a circle, too.
Hence the strategy for the detection of circular sections is:
1) Find a sphere, which intersects the quadric in a pair of planes and
2) The planes, which are parallel to the detected ones, deliver the remaining circular sections.
Tri-axial ellipsoid
tri-axial ellipsoid with circular sections (blue and green) and the auxiliary sphere (red), which intersects the quadric in the blue circlesEllipsoid intersected by spheres:
For the ellipsoid with equation
and the semi-axes one uses an auxiliary sphere with equation
The sphers's radius has to be chosen such that the intersection with the ellipsoid is contained in two planes through the origin.
Multiplication of the ellipsoid's equation by and subtracting the sphere's equation yields:
This equation describes a pair of planes, if one of the 3 coefficients is zero. In case of or the equation is only fulfilled by either the x-axis or the z-axis. Only in case of one gets a pair of planes with equation
because only in this case the remaining coefficients have different signs (due to: ).
The diagram gives an impression of more common intersections between a sphere and an ellipsoid and highlights the exceptional circular case (blue).
If the values of the semi-axes are approaching, the two pencils of planes (and circles) approach either. For all the planes are orthogonal to the z-axis (rotation axis).
Proof of property (P):
Turning the ellipsoid around the y-axis such that one of the two circles (blue) lies in the x-y-plane results in a new equation of the ellipsoid:
For one gets , which has to be the equation of a circle. This is only true, if .
The intersection of the ellipsoid by a plane with equation , (parallel to the x-y-plane) has the equation
.
This equation describes a circle or a point or the empty set. Center and radius of the circle can be found be completing the square.