This is an old revision of this page, as edited by Khassan du(talk | contribs) at 09:25, 17 November 2016(←Created page with ' :<math>\sum_{n=0}^\infty \frac{2^n}{3^{n+1}} = \frac{1}{3} + \frac{2}{9} + \frac{4}{27} + \frac{8}{81} + \cdots = \frac{1}{3}\left(\frac{1}{1-\frac{2}{3}}\righ...'). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.Revision as of 09:25, 17 November 2016 by Khassan du(talk | contribs)(←Created page with ' :<math>\sum_{n=0}^\infty \frac{2^n}{3^{n+1}} = \frac{1}{3} + \frac{2}{9} + \frac{4}{27} + \frac{8}{81} + \cdots = \frac{1}{3}\left(\frac{1}{1-\frac{2}{3}}\righ...')
