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The equivalence between the above matrix normal and multivariate normal density functions can be shown using several properties of the trace and Kronecker product, as follows. We start with the argument of the exponent of the matrix normal PDF:
which is the argument of the exponent of the multivariate normal PDF. The proof is completed by using the determinant property:
Linear transform: let D (r-by-n), be of full rankr ≤ n and C (p-by-s), be of full rank s ≤ p, then:
Example
Let's imagine a sample of n independent p-dimensional random variables identically distributed according to a multivariate normal distribution:
.
When defining the n × p matrix for which the ith row is , we obtain:
where each row of is equal to , that is , is the n × n identity matrix, that is the rows are independent, and .
Maximum Likelihood Parameter Estimation
Given k matrices, each of size n × p, denoted , which we assume have been sampled i.i.d. from a matrix normal distribution, the maximum likelihood estimate of the parameters can be obtained by maximizing:
The solution for the mean has a closed form, namely
but the covariance parameters do not. However, these parameters can be iteratively maximized by zero-ing their gradients at:
and
See for example [3] and references therein. The covariance parameters are non-identifiable in the sense that for any scale factor, s>0, we have:
Drawing values from the distribution
Sampling from the matrix normal distribution is a special case of the sampling procedure for the multivariate normal distribution. Let be an n by p matrix of np independent samples from the standard normal distribution, so that
Then let
so that
where A and B can be chosen by Cholesky decomposition or a similar matrix square root operation.