Summability kernel

In mathematics, a summability kernel is a family or sequence of periodic integrable functions satisfying a certain set of properties, listed below. Certain kernels, such as the Fejér kernel, are particularly useful in Fourier analysis. A summability kernel is a uniformly bounded approximate identity.

Definition

Let $\mathbb {T} :=\mathbb {R} /\mathbb {Z}$. A summability kernel is a sequence $(k_{n})$ in $L^{1}(\mathbb {T} )$ that satisfies

• $\int _{\mathbb {T} }k_{n}(t)\,dt=1$
• $\int _{\mathbb {T} }|k_{n}(t)|\,dt\leq M$
• $\int _{\delta \leq |t|\leq {\frac {1}{2}}}|k_{n}(t)|\,dt\to 0$ as $n\to \infty$, for every $\delta >0$.

Note that if $k_{n}\geq 0$ for all $n$, i.e. $(k_{n})$ is a positive summability kernel, then the second requirement follows automatically from the first.

If instead we take the convention $\mathbb {T} =\mathbb {R} /2\pi \mathbb {Z}$, the first equation becomes ${\frac {1}{2\pi }}\int _{\mathbb {T} }k_{n}(t)\,dt=1$, and the upper limit of integration on the third equation should be extended to $\pi$.

We can also consider $\mathbb {R}$ rather than $\mathbb {T}$; then we integrate (i) and (ii) over $\mathbb {R}$, and (iii) over $|t|>\delta$.

Examples

• The Fejér kernel
• The Poisson kernel (continuous index)
• The Dirichlet kernel is not a summability kernel, since it fails the second requirement.

Convolutions

Let $(k_{n})$ be a summability kernel, and $*$ denote the convolution operation.

• If $(k_{n}),f\in {\mathcal {C}}(\mathbb {T} )$ (continuous functions on $\mathbb {T}$), then $k_{n}*f\to f$ in ${\mathcal {C}}(\mathbb {T} )$, i.e. uniformly, as $n\to \infty$.
• If $(k_{n}),f\in L^{1}(\mathbb {T} )$, then $k_{n}*f\to f$ in $L^{1}(\mathbb {T} )$, as $n\to \infty$.
• If $(k_{n})$ is radially decreasing symmetric and $f\in L^{1}(\mathbb {T} )$, then $k_{n}*f\to f$ pointwise a.e., as $n\to \infty$. This uses the Hardy–Littlewood maximal function. If $(k_{n})$ is not radially decreasing symmetric, but the decreasing symmetrization ${\widetilde {k}}_{n}(x):=\sup _{|y|\geq |x|}k_{n}(y)$ satisfies $\sup _{n\in \mathbb {N} }\|{\widetilde {k_{n}}}\|_{1}<\infty$, then a.e. convergence still holds, using a similar argument.

References

• Katznelson, Yitzhak (2004), An introduction to Harmonic Analysis, Cambridge University Press, ISBN 0-521-54359-2