Talk:Clock angle problem

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Reverting to last sensible version

Lots of content seems to have been deleted. I've reverted back to an older edit. Apologies if I've accidently deleted some content. Nick Connolly 03:25, 12 October 2007 (UTC)[reply]

Note:

    Why is + M is needed after the  $(60H)$  in the above equation?
    Say the time is 5:24.  We can't just calculate the 5.  We need to immediately 
    and NOT separately include the minutes i.e include the 24 minutes.  Because 5:24
    means the hour handle is NOT exactly at 5 now.  Since it's 24 min past then the hour
    handle would have moved a little bit away or a little bit past from the 5 O'Clock 
    mark.

I removed this from the article and posted it here. It should be in the discussion not formally placed in an article. --Pr. Ultracrepidarian (talk) 02:03, 26 October 2010 (UTC)[reply]