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No, I wasn't wrong. a^p^x has no relevance to the p-adic exponential, even if the domains of "a", "p", and "x" are different. I was going to say that the concept of a^p^x as used here is totally different than that in double exponential function; it would be, but it isn't even used here. — Arthur Rubin(talk)21:23, 1 May 2013 (UTC)[reply]