Simple LR parser
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In computer science, an simple LR or SLR parser will typically have more conflict states than an LALR parser. For real-world computer languages, an SLR parser is usually not adequate, but for student projects in a compiler class it is a good learning tool.
A grammar that has no conflicts reported by an SLR parser generator is an SLR grammar.
Algorithm
The SLR parsing algorithm
Initialize the stack with S Read input symbol while (true) if Action(top(stack), input) = S NS <- Goto(top(stack),input) push NS Read next symbol else if Action(top(stack), input) = Rk output k pop |RHS| of production k from stack NS <- Goto(top(stack), LHS_k) push NS else if Action(top(stack),input) = A output valid, return else output invalid, return
Example
A grammar that can be parsed by an SLR parser but not by an LR(0) parser is the following:
- (0) S → E
- (1) E → 1 E
- (2) E → 1
Constructing the action and goto table as is done for LR(0) parsers would give the following item sets and tables:
- Item set 0
- S → • E
- + E → • 1 E
- + E → • 1
- Item set 1
- E → 1 • E
- E → 1 •
- + E → • 1 E
- + E → • 1
- Item set 2
- S → E •
- Item set 3
- E → 1 E •
The action and goto tables:
action | goto | ||
state | 1 | $ | E |
0 | s1 | 2 | |
1 | s1/r2 | r2 | 3 |
2 | acc | ||
3 | r1 | r1 |
As can be observed there is a shift-reduce conflict for state 1 and terminal '1'. However, the follow set of E is { $ } so the reduce actions r1 and r2 are only valid in the column for $. The result is the following conflict-less action and goto table:
action | goto | ||
state | 1 | $ | E |
0 | s1 | 2 | |
1 | s1 | r2 | 3 |
2 | acc | ||
3 | r1 |