Talk:Clock angle problem

Reverting to last sensible version

Lots of content seems to have been deleted. I've reverted back to an older edit. Apologies if I've accidently deleted some content. Nick Connolly 03:25, 12 October 2007 (UTC)[reply]

Note:

    Why is + M is needed after the  $(60H)$  in the above equation?
    Say the time is 5:24.  We can't just calculate the 5.  We need to immediately 
    and NOT separately include the minutes i.e include the 24 minutes.  Because 5:24
    means the hour handle is NOT exactly at 5 now.  Since it's 24 min past then the hour
    handle would have moved a little bit away or a little bit past from the 5 O'Clock 
    mark.

I removed this from the article and posted it here. It should be in the discussion not formally placed in an article. --Pr. Ultracrepidarian (talk) 02:03, 26 October 2010 (UTC)[reply]