Talk:Sum of normally distributed random variables

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Hi! Recently articles on Wikipedia get so good that they can be used to base a literature review on. However, very often (like in this page) "real" literature references are missing. I assume this proof was done by someone else than the author. I would like to see references. Kind regards, Steven

In this case, the problem is which of the many references to use? One could just say "See any standard textbook on the subject", and it would be essentially correct, but probably doesn't count as a "reference". Michael Hardy 18:39, 3 August 2006 (UTC)[reply]

Product?

What about the product of normally distributed random variables? I found a document that discusses it which says that if $V=XY$ then

f_{V}(v)=\int _{-\infty }^{\infty }f_{X,Y}(x,v/x){\frac {1}{|x|}}\,dx

.

But I'm having trouble finding the mean and variance of this distribution. (I suppose it might not even be normally distributed.) —Ben FrantzDale 04:57, 31 January 2007 (UTC)[reply]

This may have the answer: http://mathworld.wolfram.com/NormalProductDistribution.html —Ben FrantzDale 05:27, 31 January 2007 (UTC)[reply]

Case if the variables are correlated

For the case where the variables are correlated, I have given an outline of how to proceed with the derivation. Velocidex (talk) 02:03, 1 July 2008 (UTC)[reply]

You should also provide the covariance matrix, because the correlation coefficients are not clear. How do you get the term 2ρσ_xσ_y?. You should get 2ρ. Except if the cross correlation is ρσ_xσ_y. Energon (talk) 13:27, 16 June 2009 (UTC)[reply]

Integrating the Dirac delta function

In the section Proof using convolutions, we might want to include a note that the Dirac function is constrained to satisfy the identity

\int _{-\infty }^{\infty }\delta (x)\,dx=1.

and can thus be dropped. 192.91.171.42 (talk) 21:00, 14 April 2009 (UTC)[reply]

Geometric proof

Pretty sure there's an error here. $c={\sqrt {(Z/2)^{2}+(Z/2)^{2}}}=Z/2\,$ should read $c={\sqrt {(Z/2)^{2}+(Z/2)^{2}}}=Z/{\sqrt {2}}\,$ and ${\text{erf}}(Z/2)$ should read ${\text{erf}}(Z/{\sqrt {2}})$ .