Talk:Bounded function
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The function f:R → R defined by f (x)=sin x is bounded. The sine function is no longer bounded if it is defined over the set of all complex numbers.
why isn't sinz bounded function?
The function f:R → R defined by f (x)=sin x is bounded. The sine function is no longer bounded if it is defined over the set of all complex numbers.
why isn't sinz bounded function?