If p < s u b > 1 < / s u b > {\displaystyle p<sub>1</sub>} follows p < s u b > 0 < / s u b > {\displaystyle p<sub>0</sub>} , then p < s u b > 1 < / s u b > {\displaystyle p<sub>1</sub>} gets its coordinates from the following set of equations:
d x = p < s u p > 0 < s u b > x < / s u b >< / s u p > − p < s u b > 1 < s u b > x < / s u b >< / s u b >< b r / > d y = p 0 y − p 1 y < b r / > l < s u b > 1 < / s u b >=< s q r t > d < s u b > x < / s u b >< s u p > 2 < / s u p > + d < s u b > y < / s u b >< s u p > 2 < / s u p >< / s q r t >< b r / > p < s u b > 1 < s u b > d x < / s u b >< / s u b >= d < s u b > x < / s u b > / l < s u b > 1 < / s u b > ∗ r − d < s u b > x < / s u b >< b r / > p < s u b > 1 < s u b > d y < / s u b >< / s u b >= d < s u b > y < / s u b > / l < s u b > 1 < / s u b > ∗ r − d < s u b > y < / s u b > {\displaystyle dx=p<sup>0<sub>x</sub></sup>-p<sub>1<sub>x</sub></sub><br/>dy=p0y-p1y<br/>l<sub>1</sub>=<sqrt>d<sub>x</sub><sup>2</sup>+d<sub>y</sub><sup>2</sup></sqrt><br/>p<sub>1<sub>dx</sub></sub>=d<sub>x</sub>/l<sub>1</sub>*r-d<sub>x</sub><br/>p<sub>1<sub>dy</sub></sub>=d<sub>y</sub>/l<sub>1</sub>*r-d<sub>y</sub>}
