This is an old revision of this page, as edited by AneasSu(talk | contribs) at 12:38, 27 September 2024(Added a proof, without removing the lead section. A proof may help many learners to understand it, so if its layout is inappropriate, please be so kind to fix it instead of deleting the proof.). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.Revision as of 12:38, 27 September 2024 by AneasSu(talk | contribs)(Added a proof, without removing the lead section. A proof may help many learners to understand it, so if its layout is inappropriate, please be so kind to fix it instead of deleting the proof.)
The theorem states that the integral of a function's squared modulus is equal to the integral of the squared modulus of its frequency spectrum. That is, if is a function on the real line, and is its frequency spectrum, then
A more precise formulation is that if a function is in both Lp spaces and , then its Fourier transform is in and the Fourier transform is an isometry with respect to the L2 norm. This implies that the Fourier transform restricted to has a unique extension to a linear isometric map, sometimes called the Plancherel transform. This isometry is actually a unitary map. In effect, this makes it possible to speak of Fourier transforms of quadratically integrable functions.
Plancherel's theorem remains valid as stated on n-dimensional Euclidean space. The theorem also holds more generally in locally compact abelian groups. There is also a version of the Plancherel theorem which makes sense for non-commutative locally compact groups satisfying certain technical assumptions. This is the subject of non-commutative harmonic analysis.
Due to the polarization identity, one can also apply Plancherel's theorem to the inner product of two functions. That is, if and are two functions, and denotes the Plancherel transform, then
and if and are furthermore functions, then
and
so
Proof
Step 1. The equality holds if f is differentiable and f' is bounded
Let be a family of mollifiers, , then for each ε, , by Hölder's inequality, hence is differentiable and has a bounded derivative. By Step 1, . By the property of mollification, the left hand side converges to as , and by convolution theorem, , hence by Fatou' lemma, we have , thus is integrable. Thus the right hand side converges to as by Dominated Convergence Theorem. Q.E.D.