Huntington–Hill method
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The Huntington–Hill method (sometimes method of equal proportions) is a highest averages method for assigning seats in a representative assembly.[1] Since 1941, this method has been used to apportion the 435 seats in the United States House of Representatives following the completion of each decennial census.[2][3]
The method minimizes the relative difference in the number of constituents represented by each legislator. In other words, the method selects the algorithm such that no transfer of a seat from one state to another can reduce the percent error in representation for both states.[1]
Apportionment method
In this method, as a first step, each of the 50 states is given its one guaranteed seat in the House of Representatives, leaving 385 seats to assign. The remaining seats are allocated one at a time, to the state with the highest average district population, to bring its district population down. However, it is not clear if we should calculate the average before or after allocating an additional seat, and the two procedures give different results. Huntington-Hill uses a continuity correction to compromise, given by taking the geometric mean of both divisors, i.e.:
where P is the population of the state, and n is the number of seats it currently holds before the possible allocation of the next seat.
Consider the reapportionment following the 2010 U.S. census: after every state is given one seat:
- The largest value of A1 corresponds to the largest state, California, which is allocated seat 51.
- The 52nd seat goes to Texas, the 2nd largest state, because its A1 priority value is larger than the An of any other state.
- he 53rd seat goes back to California because its A2 priority value is larger than the An of any other state.
- The 54th seat goes to New York because its A1 priority value is larger than the An of any other state at this point.
This process continues until all remaining seats are assigned. Each time a state is assigned a seat, n is incremented by 1, causing its priority value to be reduced.
Party lists
Even though the Huntington–Hill system was designed to distribute seats in a legislature among states pursuant to census results, it can also be used, when putting parties in the place of states and votes in place of population, for the mathematically equivalent task of distributing seats among parties pursuant to an election results in a party-list proportional representation system. Unlike the D'Hondt and Sainte-Laguë systems, which allow the allocation of seats by calculating successive quotients right away, the Huntington–Hill system requires each party or state have at least one seat to avoid a division by zero error. In the U.S. House of Representatives, this is ensured by guaranteeing each state at least one seat; in party-list representation, small parties would likely be eliminated using some electoral threshold.
Examples
Each eligible party is assigned one seat. With all the initial seats assigned, the remaining five seats are distributed by a priority number calculated as follows. Each eligible party's (Parties A, B, and C) total votes is divided by √2 • 1 ≈ 1.41, then by approximately 2.45, 3.46, 4.47, 5.48, 6.48, 7.48, and 8.49. The 5 highest entries, marked with asterisks, range from 70,711 down to 28,868. For each, the corresponding party gets another seat.
For comparison, the "Proportionate seats" column shows the exact fractional numbers of seats due, calculated in proportion to the number of votes received (For example, 100,000/230,000 × 8 = 3.48). If the "Total Seats" column is less than the "Proportionate seats" column (Parties C[a] and D in this example) the party is under-represented. Conversely, if the "Total Seats" column is greater than the "Proportionate seats" column (Parties A and B in this example) the party is over-represented.[b]
Denominator | √1·2 ≈ 1.41 |
√2·3 ≈ 2.45 |
√3·4 ≈ 3.46 |
√4·5 ≈ 4.47 |
√5·6 ≈ 5.48 |
√6·7 ≈ 6.48 |
√7·8 ≈ 7.48 |
√8·9 ≈ 8.49 |
Initial seats |
Seats won (*) |
Total Seats |
Ideal seats |
---|---|---|---|---|---|---|---|---|---|---|---|---|
Party A | 70,711* | 40,825* | 28,868* | 22,361 | 18,257 | 15,430 | 13,363 | 11,785 | 1 | 3 | 4 | 3.8 |
Party B | 56,569* | 32,660* | 23,094 | 17,889 | 14,606 | 12,344 | 10,690 | 9,428 | 1 | 2 | 3 | 3.0 |
Party C | 21,213 | 12,247 | 8,660 | 6,708 | 5,477 | 4,629 | 4,009 | 3,536 | 1 | 0 | 1 | 1.1 |
Knesset example
The Knesset (Israel's unicameral legislature), are elected by party-list representation with apportionment by the D'Hondt method.[c] Had the Huntington–Hill method, rather than the D'Hondt method, been used to apportion seats following the elections to the 20th Knesset, held in 2015, the 120 seats in the 20th Knesset would have been apportioned as follows:
Party | Votes | Huntington–Hill | D'Hondt[c] | +/– | |||
---|---|---|---|---|---|---|---|
(hypothetical) | (actual) | ||||||
Last Priority[d] | Next Priority[e] | Seats | Seats | ||||
Likud | 985,408 | 33408 | 32313 | 30 | 30 | 0 | |
Zionist Union | 786,313 | 33468 | 32101 | 24 | 24 | 0 | |
Joint List | 446,583 | 35755 | 33103 | 13 | 13 | 0 | |
Yesh Atid | 371,602 | 35431 | 32344 | 11 | 11 | 0 | |
Kulanu | 315,360 | 37166 | 33242 | 9 | 10 | –1 | |
The Jewish Home | 283,910 | 33459 | 29927 | 9 | 8 | +1 | |
Shas | 241,613 | 37282 | 32287 | 7 | 7 | 0 | |
Yisrael Beiteinu | 214,906 | 39236 | 33161 | 6 | 6 | 0 | |
United Torah Judaism | 210,143 | 38367 | 32426 | 6 | 6 | 0 | |
Meretz | 165,529 | 37013 | 30221 | 5 | 5 | 0 | |
Source: CEC |
Compared with the actual apportionment, Kulanu would have lost one seat, while The Jewish Home would have gained one seat.
Footnotes
- ^ Party C's proportion is actually 1.04
- ^ While this example favors the largest parties (Parties A and B), if a different number of seats were apportioned, other parties would be favored. In short, the largest party is not always favored.
For example, if there were 12 seats instead of 8, then Party C would be the only over-represented party (since Party D would have qualified) with two full seats while proportionately deserving only 1.6 seats. - ^ a b The method used for the 20th Knesset was actually a modified D'Hondt, called the Bader-Ofer method. This modification allows for spare vote agreements between parties.[4]
- ^ This is each party's last priority number which resulted in a seat being gained by the party. Likud gained the last seat (the 120th seat allocated). Each priority number in this column is greater than any priority number in the Next Priority column.
- ^ This is each party's next priority number which would result in a seat being gained by the party. Kulanu would have gained the next seat (if there were 121 seats in the Knesset). Each priority number in this column is less than any priority number in the Last Priority column.
References
- ^ a b "Congressional Apportionment". NationalAtlas.gov. Archived from the original on 2009-02-28. Retrieved 2009-02-14.
- ^ "U.S. Code Title 2, Section 2a: Reapportionment of Representatives".
- ^ "Computing Apportionment". United States Census Bureau. Retrieved 2021-04-26.
- ^ "With Bader-Ofer method, not every ballot counts". The Jerusalem Post. Retrieved 2021-05-04.