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Projective tensor product

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Given locally convex topological vector spaces and , the projective topology, or π-topology, is the strongest topology on the vector space which makes it a locally convex topological vector space such that the canonical map (from to ) is continuous. When equipped with this topology, is called the projective tensor product of and .

Properties

Throughout, all spaces are assumed to be locally convex topological vector spaces unless stated otherwise. When referring to a topological space, the symbol denotes the projective tensor product unless stated otherwise.

  • is Hausdorff if and only if both and are Hausdorff.[1]
  • If both and are metrizable (resp. semi-metrizable, normable, semi-normable) then so is
  • For any two continuous linear operators and , their tensor product is continuous.[2]
  • When are Banach spaces, each map has a unique continuous extension to the completion of .
  • If and are Frechet spaces then is barelled.[3]
  • For any and collection , the canonical map is an isomorphism of topological vector spaces.[3]
  • If and are nuclear then and are nuclear.[4]
  • In general, the projective tensor product does not respect subspaces (e.g. if is a vector subspace of then the TVS has in general a coarser topology than the subspace topology inherited from ).[5]
  • If and are complemented subspaces of and respectively, then is a complemented vector subspace of and the projective norm on is equivalent to the projective norm on restricted to the subspace . Furthermore, if and are complemented by projections of norm 1, then is complemented by a projection of norm 1.[5]
  • If is an isometric embedding into a Banach space then its unique continuous extension is also an isometric embedding.
  • Let and be vector subspaces of the Banach spaces and respectively. Then is a TVS-subspace of if and only if every bounded bilinear form on extends to a continuous bilinear form on with the same norm.[6]

Normed spaces

Suppose now that and are normed spaces. Then is a normable space with a canonical norm denoted by The -norm is defined on by where is the balanced convex hull of Given in this can also be expressed as[7] where the infimum is taken over all finite sequences and (of the same length) such that If is in then where the infimum is taken over all (finite or infinite) sequences and (of the same length) such that [8] If and are Banach spaces then the closed unit ball of is the closed convex hull of the tensor product of the closed unit ball in with that of [9]

The projective tensor product

Tensor product of seminorms

For a seminorm on , let denote its closed unit ball.

If is a seminorm on and is a seminorm on , we define the tensor product of and to be the map defined on by where is the balanced convex hull of Given in this can also be expressed as[7] where the infimum is taken over all finite sequences and (of the same length) such that (recall that it may not be possible to express as a simple tensor). If then we have The seminorm is a norm if and only if both and are norms.[1]

If the topology of is given by the family of seminorms , and that of by the seminorms , then the topology on the vector space generated by the seminorms is identical to the projective topology. In particular, if and are seminormed spaces with seminorms and respectively, then is a seminormable space whose topology is defined by the seminorm [10]

Universal property

For any locally convex topological vector space topology on ( with this topology will be denoted by ), then is identical to the projective topology if and only if it has the following property:[11]

For every locally convex if is the canonical map from the space of all bilinear mappings of the form going into the space of all linear mappings of then when the domain of is restricted to then the range of this restriction is the space of continuous linear operators

In particular, the continuous dual space of the projective tensor product is canonically isomorphic to the space of continuous bilinear forms on .

Completion

In general, the space is not complete, even if both and are complete (in fact, if and are both infinite-dimensional Banach spaces then is necessarily not complete[12]). However, can always be linearly embedded as a dense vector subspace of some complete locally convex TVS, which is generally denoted by via a linear embedding.

The continuous dual space of is the same as that of , namely, the space of continuous bilinear forms .[13]

Grothendieck's representation of elements in the completion

In a Hausdorff locally convex space a sequence in is absolutely convergent if for every continuous seminorm on [14] We write if the sequence of partial sums converges to in [14]

The following fundamental result in the theory of topological tensor products is due to Alexander Grothendieck.[15]

TheoremLet and be metrizable locally convex TVSs and let Then is the sum of an absolutely convergent series where and and are null sequences in and respectively.

The next theorem shows that it is possible to make the representation of independent of the sequences and

Theorem[16]Let and be Fréchet spaces and let (resp. ) be a balanced open neighborhood of the origin in (resp. in ). Let be a compact subset of the convex balanced hull of There exists a compact subset of the unit ball in and sequences and contained in and respectively, converging to the origin such that for every there exists some such that

Topology of bi-bounded convergence

Let and denote the families of all bounded subsets of and respectively. Since the continuous dual space of is the space of continuous bilinear forms we can place on the topology of uniform convergence on sets in which is also called the topology of bi-bounded convergence. This topology is coarser than the strong topology on B(X, Y), and in (Grothendieck 1955), Alexander Grothendieck was interested in when these two topologies were identical. This question is equivalent to the questions: Given a bounded subset do there exist bounded subsets and such that is a subset of the closed convex hull of ?

Grothendieck proved that these topologies are equal when and are both Banach spaces or both are DF-spaces (a class of spaces introduced by Grothendieck[17]).[clarification needed] They are also equal when both spaces are Fréchet with one of them being nuclear.[13]

Strong dual and bidual

Given a locally convex TVS is assumed to have the strong topology (so ) and unless stated otherwise, the same is true of the bidual (so Alexander Grothendieck characterized the strong dual and bidual for certain situations:

Theorem[18] (Grothendieck)Let and be locally convex TVSs with nuclear. Assume that both and are Fréchet spaces or else that they are both DF-spaces. Then:

  1. The strong dual of can be identified with ;
  2. The bidual of can be identified with ;
  3. If in addition is reflexive then (and hence ) is a reflexive space;
  4. Every separately continuous bilinear form on is continuous;
  5. The strong dual of can be identified with so in particular if is reflexive then so is

Trace form

Suppose that is a locally convex spaces. There is a bilinear form on defined by which when is a Banach space has norm equal to 1. This bilinear form corresponds to a linear form on given by mapping to (where of course this value is in fact independent of the representation of chosen). Letting have its strong dual topology, we can continuously extend this linear map to a map (assuming that the vector spaces have scalar field ) called the trace of This name originates from the fact that if we write where if and 0 otherwise, then [19]

Duality with L(X; Y')

Assuming that and are Banach spaces over the field one may define a dual system between and with the duality map defined by where is the identity map and is the unique continuous extension of the continuous map If we write with and the sequences and each converging to zero, then we have[20]

Examples

Space of absolutely summable families

Throughout this section we fix some arbitrary (possibly uncountable) set a TVS and we let be the directed set of all finite subsets of directed by inclusion

Let be a family of elements in a TVS and for every finite subset of let We call summable in if the limit of the net converges in to some element (any such element is called its sum). We call absolutely summable if it is summable and if for every continuous seminorm on the family is summable in [21] The set of all such absolutely summable families is a vector subspace of denoted by

Note that if is a metrizable locally convex space then at most countably many terms in an absolutely summable family are non-0. A metrizable locally convex space is nuclear if and only if every summable sequence is absolutely summable.[22] It follows that a normable space in which every summable sequence is absolutely summable, is necessarily finite dimensional.[22]

We now define a topology on in a very natural way. This topology turns out to be the projective topology taken from and transferred to via a canonical vector space isomorphism (the obvious one). This is a common occurrence when studying the injective and projective tensor products of function/sequence spaces and TVSs: the "natural way" in which one would define (from scratch) a topology on such a tensor product is frequently equivalent to the projective or injective tensor product topology.

Let denote a base of convex balanced neighborhoods of the origin in and for each let denote its Minkowski functional. For any such and any let where defines a seminorm on The family of seminorms generates a topology making into a locally convex space. The vector space endowed with this topology will be denoted by [21] The special case where is the scalar field will be denoted by

There is a canonical embedding of vector spaces defined by linearizing the bilinear map defined by [21]

Theorem[21]The canonical embedding (of vector spaces) becomes an embedding of topological vector spaces when is given the projective topology and furthermore, its range is dense in its codomain. If is a completion of then the continuous extension of this embedding is an isomorphism of TVSs. So in particular, if is complete then is canonically isomorphic to

See also

References

  1. ^ a b Trèves 2006, p. 437.
  2. ^ Trèves 2006, p. 439.
  3. ^ a b Trèves 2006, p. 445.
  4. ^ Schaefer & Wolff 1999, p. 105.
  5. ^ a b Ryan 2002, p. 18.
  6. ^ Ryan 2002, p. 24.
  7. ^ a b Trèves 2006, p. 435.
  8. ^ Ryan 2002, pp. 21–22.
  9. ^ Ryan 2002, p. 17.
  10. ^ Trèves 2006, p. 437-438.
  11. ^ Trèves 2006, p. 438.
  12. ^ Ryan 2002, p. 43.
  13. ^ a b Schaefer & Wolff 1999, p. 173.
  14. ^ a b Schaefer & Wolff 1999, p. 120.
  15. ^ Schaefer & Wolff 1999, p. 94.
  16. ^ Trèves 2006, pp. 459–460.
  17. ^ Schaefer & Wolff 1999, p. 154.
  18. ^ Schaefer & Wolff 1999, pp. 175–176.
  19. ^ Trèves 2006, pp. 485–486.
  20. ^ Trèves 2006, p. 496.
  21. ^ a b c d Schaefer & Wolff 1999, pp. 179–184.
  22. ^ a b Schaefer & Wolff 1999, p. 184.

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