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Talk:Midpoint method

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This is an old revision of this page, as edited by Oleg Alexandrov (talk | contribs) at 00:48, 12 February 2007 (reply on accuracy). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Accuracy

This method looks like it will always be less acurate, and require more computation than the Euler method done with step size h/2. —The preceding unsigned comment was added by Neiljackson (talk • contribs).

That is not correct. The midpoint method gives an accuracy of O(h^3), compared to O(h^2) for Euler's method. So overall you gain by using this instead of Euler's method, even in spite of more computation involved. Oleg Alexandrov (talk) 00:48, 12 February 2007 (UTC)[reply]
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