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Talk:Hartogs's theorem on separate holomorphicity

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This is an old revision of this page, as edited by Silvermatsu (talk | contribs) at 10:24, 3 February 2021 (For real variables Separate continuity (differentiable) is not a condition of continuity.(Set priority scale to mid. However, it may be borne in mind that there are many cases in which the Osgood's lemma is sufficient, as function theory often requires that the function be continuous. ) No proof sketch is written.(Set quality scale start)). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.
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Does the result imply that the function is actually analytic or just continuous? --ComplexZeta

Well, it implies continuity, and from there it is rather easy to get analyticity. Oleg Alexandrov (talk) 04:41, 21 June 2006 (UTC)[reply]

Incomplete definition of function

The function used as a counterexample is not defined at 0. I would fix it but I see the mistake actually comes from PlanetMath. -Set theorist (talk) 09:10, 25 November 2010 (UTC)[reply]

The proper function in this case is defined piecewise as f(x,y) = xy(x^2-y^2)/(x^2 + y^2) except at the origin, where f = 0. --Moly 21:24, 6 January 2011 (UTC) — Preceding unsigned comment added by Moly (talkcontribs)