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Max-flow min-cut theorem: Revision history


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  • curprev 01:5101:51, 3 October 2019 1.129.111.51 talk 23,333 bytes +1 Project selection problem: grammar undo
  • curprev 01:4901:49, 3 October 2019 1.129.111.51 talk 23,332 bytes +606 Example: Note that the flow through each of the dashed edges is at full capacity: this is the 'bottleneck' of the system. By contrast there is spare capacity in the right-hand part of the network. In particular, the flow from node one to node two need not be equal to 1. If there were no flow between nodes one and two, then the inputs to the sink would change to 4/4 and 3/5; the total flow would still be seven (4+3=7). On the other hand, if the flow from node one to node two were doubl undo
  • curprev 01:4201:42, 3 October 2019 1.129.111.51 talk 22,726 bytes +238 Example: The numerical annotation on each arrow, in the form ''x''/''y'', indicate the actual flow (''x'') and the maximum flow capacity (''y''). The flows emanating from the source total seven (3+4=7), as do the flows into the sink (4+3=7). undo
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