Jump to content

Integration using Euler's formula: Revision history


For any version listed below, click on its date to view it. For more help, see Help:Page history and Help:Edit summary. (cur) = difference from current version, (prev) = difference from preceding version, m = minor edit, → = section edit, ← = automatic edit summary

(newest | oldest) View (newer 50 | ) (20 | 50 | 100 | 250 | 500)

20 April 2025

15 January 2025

12 January 2025

12 December 2024

2 November 2024

28 July 2024

20 April 2024

17 March 2024

4 January 2024

3 August 2022

2 June 2021

18 April 2021

29 March 2021

17 March 2021

23 January 2021

18 July 2020

26 April 2020

5 April 2020

11 July 2019

19 March 2019

10 March 2019

  • curprev 00:0300:03, 10 March 2019 2601:588:4100:5cbc:2144:33ea:5343:b28a talk 4,505 bytes +2 Fractions: 6 was supposed to be 12, since when changing the expression using Euler’s identity, 1/2 can be factored out from the denominator. The 1/2 is multiplied in the numerator, yielding 2+(e^2ix/2)+4-(e^-2ix). Like terms 4 and 2 can be added to simplify the expression. You could multiply by 2/2, which is why the 1/2 is out of the integral, but the simplfied 6 should be multiplied by 2 as well. Error carry forward for the next question. undo Tags: Mobile edit Mobile web edit

20 June 2018

6 March 2018

9 October 2017

21 September 2017

14 June 2017

12 February 2017

23 October 2016

10 October 2016

20 July 2016

9 July 2016

25 May 2016

(newest | oldest) View (newer 50 | ) (20 | 50 | 100 | 250 | 500)