Talk:Developable surface

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In mathematics, a developable surface is a surface with zero Gaussian curvature.

Wondering if having everywhere zero curvature implies that the surface is developable? If so is their a proof of the result? --Salix alba (talk) 19:55, 27 February 2007 (UTC)[reply]

By definition, surface is developable if and only if it has zero Gaussian curvature (sum of angles of any triangle on that surface always equals to 180°). Admiral Norton ^(talk) 20:57, 19 February 2008 (UTC)[reply]